2(x³-2y²)-(x-2y)-(x-3y²+2x³)其中x=﹣3,y=﹣2
2(x³-2y²)-(x-2y)-(x-3y²+2x³)其中x=﹣3,y=﹣2
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
因式分解x²(x-2y)+y²(2y-x)
5X²-3Y²-(X²-Y²)-2(X²+4Y²)其中|X+
先化简再求值:(x-2y)²-(x+2y)(x-2y)-(x-3y)(x-y).其中x²+9y
[(2x+y)²-y(y+4x)-8x] ÷2x 其中x=2,y=-1
先化简,再求值:x²/x-y-y²/x-y,其中x=1+2又根号3
已知一个多项式加﹣2x³+4x²y+5y³得到X³-3X²Y+2Y
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
先化简再求值 (X²-Y²)-3(2X²-3Y²)其中X=2,Y=-3
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y