sets:num:a,v,t,x,y;endsetsdata:num =1..4;y2=760;vc=1.5;endda
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:综合作业 时间:2024/07/17 08:51:40
sets:
num:a,v,t,x,y;
endsets
data:
num =1..4;
y2=760;
vc=1.5;
enddata
min=m;
m=ma+mb;
mb=@sum(num(i):t(i));
x2=(vc*@cos(aq)+2.28)*ma;
y2=(vc*@sin(aq))*ma;
@for(num(i):v(i)=2.28/4*i);
@for(num(i):y(i)=2.28/4)
@for(num(i):x(i)=(vc*@cos(a(i))+v(i))*t(i));
@for(num(i):y(i)=(vc*@sin(a(i))*t(i)));
1000=@sum(num(i):x2+2*x(i));
1160=@sum(num(i):y2+2*y(i));
end
我这是一段渡河的程序 横向距离1000米 纵向1160 但是横向不能实现 需要超出1000米 可以拐出去在拐回来 用程序怎么编?
num:a,v,t,x,y;
endsets
data:
num =1..4;
y2=760;
vc=1.5;
enddata
min=m;
m=ma+mb;
mb=@sum(num(i):t(i));
x2=(vc*@cos(aq)+2.28)*ma;
y2=(vc*@sin(aq))*ma;
@for(num(i):v(i)=2.28/4*i);
@for(num(i):y(i)=2.28/4)
@for(num(i):x(i)=(vc*@cos(a(i))+v(i))*t(i));
@for(num(i):y(i)=(vc*@sin(a(i))*t(i)));
1000=@sum(num(i):x2+2*x(i));
1160=@sum(num(i):y2+2*y(i));
end
我这是一段渡河的程序 横向距离1000米 纵向1160 但是横向不能实现 需要超出1000米 可以拐出去在拐回来 用程序怎么编?
从语法上讲,只是“@for(num(i):y(i)=2.28/4)”这一句(倒数第六行)少一个分号,但是改过后运行被告知没有可行解.
sets:num:a,v,t,x,y;endsetsdata:num =1..4;y2=760;vc=1.5;endda
int num=4;if(num=1) cout
Lingo MODEL:SETS:\x05site/s1..s13/:x,y;ENDSETSDATA:\x05Y= 53
Printf (“Oct=%o;Hex=%x;\n",num,num); Printf("dec=%d\n",n);
for (num=0,count=1;num
java中 num=num>>1;这句语句是什么意思,
#include"stdio.h" num() { extern int x,y; int a=15,b=10; x=a
lingo程序:model:sets:product/1..3/:a,b; row/1..5/:c,d,y; num/1
lingo 错误11 p/1..40/:y;m(p,p):v,x;endsetsdata:v=@ole('D:\
#incluevoid num(){extern int x,y; int a=15,b=10;x=a-b;y=a+b}
若以下整型变量,且num=sum=7;则计算表达式sum=num++,sum++,++num后sum的值.B 1.首先赋
num = int.Parse(textBox1.Text);