A=INT(-0.8),B=MOD(7,7),C=RIGHT(78928,2),计算C-A-B是多少?
A=INT(-0.8),B=MOD(7,7),C=RIGHT(78928,2),计算C-A-B是多少?
#include int func(int a,int b) { int c; c=a+b;return c; } ma
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c;
#include int max(int a,int b,int c){\x05a=a>b?a :b ;\x05retu
int a,b,c;a=b=c=1;++a||++b&&++c;计算后a,b,
#include func(int a,int b) {int c; c=a+b; return c;} main()
如int b=7;float a=2.5,c=4.7;则表达式a+(int)(b/3*(int)(a+c)/2%4
int b=7;float a=2.5,c=4.7;运算下列a+(int)(b/3*(int)(a+c)/2)%4答案为
#include func(int a,int b){int c; c=a+b;returnc;}main(){intX
#include int main() { using namespace std; int a=3,b=7,c; c=
void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { in
func(int a,int b) {int c; c=a+b; return(c); } main() {int x=