如题：因式分解：x^2y-y^2z+z^2x-x^2z+y^2x+z^2y-zxyz

如题：因式分解：x^2y-y^2z+z^2x-x^2z+y^2x+z^2y-zxyz (y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z 因式分解 (x+y+z)^2+yz(y+z)+xyz x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y) 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x 因式分解：25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y) (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x- 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (x+y+z)^2-(x-y-z)^2 分式约分:(y+z-x)/{x^2-(y+z)^2} (x+y-z)^2-(x-y+z)^2=?