函数 f(x)=ln(x+1) 曲线y=f(x)在点(x0,y0)处的切线方程为 y=g(x) ,证明,对所有x属于(-
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函数 f(x)=ln(x+1) 曲线y=f(x)在点(x0,y0)处的切线方程为 y=g(x) ,证明,对所有x属于(-1,+∞)f(x)小于等于g(x)
![函数 f(x)=ln(x+1) 曲线y=f(x)在点(x0,y0)处的切线方程为 y=g(x) ,证明,对所有x属于(-](/uploads/image/z/3661609-49-9.jpg?t=%E5%87%BD%E6%95%B0+f%28x%29%3Dln%28x%2B1%29+%E6%9B%B2%E7%BA%BFy%3Df%28x%29%E5%9C%A8%E7%82%B9%28x0%2Cy0%29%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BA+y%3Dg%28x%29+%2C%E8%AF%81%E6%98%8E%2C%E5%AF%B9%E6%89%80%E6%9C%89x%E5%B1%9E%E4%BA%8E%EF%BC%88-)
f'(x) = 1/(x + 1)
点(x0,y0)处的切线方程为:y - ln(x₀ + 1) = (x - x₀)/(x₀ + 1)
y = g(x) = (x - x₀)/(x₀ + 1) + ln(x₀ + 1)
h(x) = g(x) - f(x) = (x - x₀)/(x₀ + 1) + ln(x₀ + 1) - ln(x + 1)
h'(x) = 1/(x₀ + 1) - 1/(x + 1) = (x - x₀)/[(x₀ + 1)(x + 1)]
x > -1,x₀ > -1,x₀ + 1 > 0,x + 1 > 0
-1 < x < x₀:h'(x) < 0,减函数
x > x₀:h'(x) > 0,增函数
x = x₀时,h(x)取最小值,h(x₀) = (x₀ - x₀)/(x₀ + 1) + ln(x₀ + 1) - ln(x₀ + 1) = 0
即x > -1,g(x) ≥ f(x)
点(x0,y0)处的切线方程为:y - ln(x₀ + 1) = (x - x₀)/(x₀ + 1)
y = g(x) = (x - x₀)/(x₀ + 1) + ln(x₀ + 1)
h(x) = g(x) - f(x) = (x - x₀)/(x₀ + 1) + ln(x₀ + 1) - ln(x + 1)
h'(x) = 1/(x₀ + 1) - 1/(x + 1) = (x - x₀)/[(x₀ + 1)(x + 1)]
x > -1,x₀ > -1,x₀ + 1 > 0,x + 1 > 0
-1 < x < x₀:h'(x) < 0,减函数
x > x₀:h'(x) > 0,增函数
x = x₀时,h(x)取最小值,h(x₀) = (x₀ - x₀)/(x₀ + 1) + ln(x₀ + 1) - ln(x₀ + 1) = 0
即x > -1,g(x) ≥ f(x)
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