若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
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若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z=0
zx/﹙z+2x﹚=3③
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z=0
zx/﹙z+2x﹚=3③
![若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则](/uploads/image/z/3805971-51-1.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%2Cz%E6%BB%A1%E8%B6%B3%E6%96%B9%E7%A8%8B%E7%BB%84+xy%2F%EF%B9%99x%2B2y%EF%B9%9A%3D1%E2%91%A0+yz%2F%EF%B9%99y%2B2z%EF%B9%9A%EF%BC%9D2%E2%91%A1+zx%2F%EF%B9%99z%2B2x%EF%B9%9A%E2%91%A2+%E5%88%99)
对等式①,②,③取倒数可得
2/x + 1/y = 1 (1)
2/y + 1/z = 1/2 (2)
2/z + 1/x = 1/3 (3)
(1)* 4 - (2)*2 + (3)可得9/x = 10/3,x=27/10,
把x=27/10带入(1)可得y= 27/7,
把x=27/10带入(3)可得z= -54.
所以10x+7y+z=0,答案为D.
2/x + 1/y = 1 (1)
2/y + 1/z = 1/2 (2)
2/z + 1/x = 1/3 (3)
(1)* 4 - (2)*2 + (3)可得9/x = 10/3,x=27/10,
把x=27/10带入(1)可得y= 27/7,
把x=27/10带入(3)可得z= -54.
所以10x+7y+z=0,答案为D.
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
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