2^log4(√3+2)^2+3^log9(√3-2)^2=

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/07/16 23:48:00

log4(√3+2)^2=log2(√3+2),log9(√3-2)^2=log3(√3-2).
2^log4(√3+2)^2+3^log9(√3-2)^2
=2^log2(√3+2)+3^log3(√3-2)
=(√3+2)+(√3-2)
=2√3
再问：为什么2^log2和3^log3能直接约掉啊？
再答：有公式：a^loga(N)=N

计算:(log4 3+log8 3)×log9 √2=? [log4(3)/log4(8)][log3(2)log9(2)] 2^log4(√3+2)^2+3^log9(√3-2)^2= 化简(log4(3)+log8(3))(log3(2)+log9(2)) (log4^3+log8^3)(log3^2+log9^2) 求值(log4(3)+log8(3))×(log3(2)+log9(2)) 求值(log3(2)+log9(2))*(log4(3)+log8(3)) (log3 2+log9 2)*(log4 3+log8 3)求值计算log9(根号2)*[log4(3)+log8(3)] (log3^2 + log9^4)×(log4^3 + log8^3) [log2(3)+log4(9)][log3(4)+log9(2)]等于求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)