化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/08 06:41:48
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
![化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)](/uploads/image/z/3985188-60-8.jpg?t=%E5%8C%96%E7%AE%80%5B2sin50%C2%B0%2Bsin10%C2%B0%281%2B%E2%88%9A3tan10%C2%B0%29%5D+%E2%88%9A%282sin280%C2%B0%29)
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)
= [2sin50 + sin10(cos10+√3sin10)/cos10]•√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)•√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]•√2
= 2sin(50+10)•√2
= √6
= [2sin50 + sin10(cos10+√3sin10)/cos10]•√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)•√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]•√2
= 2sin(50+10)•√2
= √6
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
[2sin50°+sin10°(1+根号3tan10°)]乘sin10°等于?
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
化简[2sin50°+sin10°(1+3tan10°)]1+cos20°
化简:[2sin50°+sin10°(1+根号3*tan10°)]*根号sin^280°
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
2sin50 +sin10×(1+ √3tan10)