sql 中 select * from A left join B on A.id=B.id where A.id=?如
sql 中 select * from A left join B on A.id=B.id where A.id=?如
sql函数,select count(A.abc) as sum from A left join B on A.id=
select ** from A where A.id in (select id from B where ****)
sql如何取交集有这样两条sql语句select distinct id from a where id='123'se
select distinct A.* from A,B where A.id = B.g_id and A.fwzid
delete from A where a_id in (select id from B where b_id in
sql = "Select * from product_series order by index desc,id a
sql="select * from "&data&" where id="&myid&"" 在数据库中没有data 这
请教sql语句,像select …from wsdy_zb t where t.id =:id order by no
请问sql="select * from 招聘信息 order by id
ORACLE 中 select B.f from a A left join b B on A.e=B.e 如果B.f为
$id="select id from account where name='".$_SESSION['login']