因式分解:(a^2-3a)^2+4a^2-12a+4=___________ n(n+1)(n+2)(n+3)+1=——
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因式分解:(a^2-3a)^2+4a^2-12a+4=___________ n(n+1)(n+2)(n+3)+1=——————
(x^2-x)^2-8x^2+8x+12=_____________
(x^2-x)^2-8x^2+8x+12=_____________
1 (a^2-3a)^2+4a^2-12a+4
=(a²-3a)²+4(a²-3a)+4
=(a²-3a+2)²
=[(a-1)(a-2)]²
=(a-1)²(a-2)²
2.n(n+1)(n+2)(n+3)+1
=[n(n+3)][(n+1)(n+2)]+1
=(n²+3n)[(n²+3n)+2]+1
=(n²+3n)²+2(n²+3n)+1
=(n²+3n+1)²
3.(x^2-x)^2-8x^2+8x+12
=(x²-x)²-8(x²-x)+12
=(x²-x-2)(x²-x-6)
=(x-2)(x+1)(x-3)(x+2)
=(a²-3a)²+4(a²-3a)+4
=(a²-3a+2)²
=[(a-1)(a-2)]²
=(a-1)²(a-2)²
2.n(n+1)(n+2)(n+3)+1
=[n(n+3)][(n+1)(n+2)]+1
=(n²+3n)[(n²+3n)+2]+1
=(n²+3n)²+2(n²+3n)+1
=(n²+3n+1)²
3.(x^2-x)^2-8x^2+8x+12
=(x²-x)²-8(x²-x)+12
=(x²-x-2)(x²-x-6)
=(x-2)(x+1)(x-3)(x+2)
因式分解:(a^2-3a)^2+4a^2-12a+4=___________ n(n+1)(n+2)(n+3)+1=——
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