如图,已知AB‖CD,OA=OD,延长OA到E,延长OD到F,使AE=DF.求证△OEB全等于△OFC
如图,已知AB‖CD,OA=OD,延长OA到E,延长OD到F,使AE=DF.求证△OEB全等于△OFC
如图,已知ABⅡCD,OA=OD,AE=DF,求证:BEⅡCF.
如图,AB=CD,AE⊥BC于E,DF⊥BC于F,AD交EF于O,OA=OD,求证:BF=CE
如图,已知AB//CD.OA=OD,点F.D.O.A.E在同一条线上,AE=DF,求证,EB//CF
如图,已知AB‖CD,OA=OD,AE=DF,求证①△ABE≡△DCF②EB‖CF
如图,已知AB‖CD,BC/EF相交于点O,OA=OD,AE=DF,求证:EB‖CF
如图AB=CD,BE=CF,AE=DF求证OA=OD
如图,AB∥CD,OA=OD,点F、D、O、A、E在同一直线上,AE=DF,求证:EB∥CF.
ab=cd,ae垂直于e,df垂直于bc于f,ad交ed于o,oa=od,求证:bf=ce
已知BC,EF交点O,AB//CD,OA=OD,AE=DF,求证BE//CF
已知:如图,AB,CD相交于点O,AC‖DB,OC=OD,E,F为AB上两点,且AE=BF,求证:CE//DF
已知:如图,AB、CD相交于点O,AC‖DB,OC=OD,E、F为AB上两点,且AE=BF,求证:CE//DF.