(-√2+√3i)-【√3-√2)+(√3+√2)i】+(-√2i+√3)
计算((-1+√3i)^3/(1+i)^6)+((-2+i)/(1+2i))
((-1+√3i)^3/(1+i)^6)-((-2+i)/(1+2i))过程怎么写
(-1+√3i)^3/(1+i)^6+(-2+i)/(1+2i)的值是
[(1-√3i)^5-(1+√3i)^4]/[i*(-1+i^8)*(1/2+1/2i)]的答案是2√3-4i,
(x-1-√2i)(x-1+√2i)(x-2+√3i)(x-2-√3i)
(3i/√2-i)^2的虚部是多少?
复数的运算 计算(2+5i)÷3i+(√3+i)(√3-i)求解答步骤
(-√2+√3i)-【√3-√2)+(√3+√2)i】+(-√2i+√3)
i^0!+i^1!+i^2!+i^3!+...+i^100!
已知复数z1=√3-i及z2=-1/2+√3/2i
计算或化简:(1)I1-√2I+I√2-√3I+I√3-2I;(2)³√6﹣π﹣2(精确到0.01)
复数(1+√3i)/(√3-i)=