sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)=
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值
2(sinθ+cosθ)= 2√2sin(θ+π/4)为什么?; (-π/2
1.已知2sin(3π+θ)=cos(π+θ),求2sin
(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
已知α、β≠kπ+π2(k∈Z),且sinθ+cosθ=2sinα , sinθcosθ=sin
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos