1/x²+x+1/x²+3x+2+1/x²+5x+6+1/x²+7x+12,分式
1/x²+x+1/x²+3x+2+1/x²+5x+6+1/x²+7x+12,分式
分式方程【初二数学】x+5/x²-x + 6/1-x =3/x
解分式方程1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)1/(x
(x-1)²/x(x²-1)×x+x²/x-x²分式的乘除
约分下列分式(x-y)/(y-x)³(x²-9)/(6-2x)(x²-1)/(x-x
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
((x²-5x+6)/(12-7x+x²))²÷((x²+3x+2)/(x
已知X+1/X=2,求分式X²+X+1/3X²-5X+3
化简分式:1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)
化简分式x²+3x+2分之1+x²+5x+6分之1+x²+7x+12分之1
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
解分式方程:1.5x/x+1-x/x+6=4. 2.x²+1/x+2x/x²+1=3