=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2
=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2
设x=ln(1+t²) y=t-arctant 求dy/dx d²y/dx²
x=ln(1+t^2),y=t-arctant 求d^2y/dx^2的导数,
设{x=ln√(1+t^2),y=arctant,求 dy/dx及d^2·y/d·x^2
方程组 x=ln√1+t^2 y=arctant 求 dy/dx
x=ln(1+t^2),y=arctant+π 求dy/dx和d2y/dx2
设参数函数x=ln(1+t^2),y=t-arctant.求(d^2y)/(dx^2).
参数方程的二阶导数中d^2y/dx^2=(d/dx)(dy/dx)=(d/dt)(1/dx/dt)(dy/dx),是一个
dx/dt=6t+2,dy/dt=(3t+1)sin(t^2),求d^2y/dx^2
求dy/dx.x=ln(1+t²),y=t-arctant求详细步骤.不要只给答案.
【急】求由参数方程组{x=ln根号(1+t^2),y=arctant所确定函数的一阶导数dy/dx和二阶导数d^2y/d
方程组 x=ln√1+t^2 y=arctant 求 dy/dx 包含了哪些知识点