设f(x)≥0,在[a,b]上连续且∫(0,1)f(x)dx=0,试证:在[a,b]上有f(x)=0
设f‘(x)在[a,b]上连续,且f(a)=0,证明:|∫b a f(x)dx|
设f(x)≥0,在[a,b]上连续且∫(0,1)f(x)dx=0,试证:在[a,b]上有f(x)=0
设f(x)在[a,b]上连续,且f(x)>0,证明:∫b a f(x)dx*∫b a 1/f(x)dx≥(b-a)^2
设 f(x)在〔a,b〕上具有一阶连续导数,且|f‘ (x)|≤M,f(a)=f(b)=0,求证∫(a,b)f(x)dx
设f(x)在[a,b]上连续,且f(x)>0,证明:至少存在一点ξ∈(a,b),使得∫f(x)dx=∫f(x)dx.(左
f(x)在[a,b]上连续,在(a,b) 内可导,且 f '(x)≤0,F(x)=1/(x-a)∫(x-a)f(t)dt
设函数f(x)在[a,b]上连续,在(a,b)内有二阶导数,且有f(a)=f(b)=0,f(c)>0(a
设f(x)在[a,b]上有连续二阶导函数,且f(a)=f(b)=0,证明∫[a,b][2f(x)-(x-a)(x-b)f
设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b
设函数f(x)在[a,b]上连续,证明:∫(a→b)f(x)dx=(b-a)∫(0→1)f[a+(b-a)x]dx
设f(x) 在[a,b] 上连续,且f(x)>0.求证:∫(a,b)f(x)dx*∫(a,bdx/f(x)≥(b-a)^
定积分的高数数学题设函数f(x)在区间[a,b]上连续,且f(x)>=0,若∫(b a)f(x)dx=0,证明f(x)恒