- -问几道数学题,1.简便计算:(3X+2Y)²(3X-2Y)²2:计算:(2X+6)²
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- -问几道数学题,
1.简便计算:(3X+2Y)²(3X-2Y)²
2:计算:(2X+6)²-2(3-X)²
3.填空:X²+10X+( )=( )²
4.试说明两个连续奇数的平方差一定是8的倍数[用n表示]
5.计算:(2ń+1)(2ń+1)(2ń+1).(2ń+1)
*题目中ń分别为2.4.8.32
1.简便计算:(3X+2Y)²(3X-2Y)²
2:计算:(2X+6)²-2(3-X)²
3.填空:X²+10X+( )=( )²
4.试说明两个连续奇数的平方差一定是8的倍数[用n表示]
5.计算:(2ń+1)(2ń+1)(2ń+1).(2ń+1)
*题目中ń分别为2.4.8.32
![- -问几道数学题,1.简便计算:(3X+2Y)²(3X-2Y)²2:计算:(2X+6)²](/uploads/image/z/823782-30-2.jpg?t=-+-%E9%97%AE%E5%87%A0%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%2C1.%E7%AE%80%E4%BE%BF%E8%AE%A1%E7%AE%97%3A%283X%2B2Y%29%26sup2%3B%283X-2Y%29%26sup2%3B2%3A%E8%AE%A1%E7%AE%97%3A%282X%2B6%29%26sup2%3B)
1.
(3X+2Y)²(3X-2Y)²
=[(3x+2y)(3x-2y)]²
=(9x-4y)²
=81x²-72xy+4y²
2.
(2X+6)²-2(3-X)²
=4(x+3)²-2(x+3)²
=2(x+3)²
=4x²+24x+36
3.填空:X²+10X+(25)=(x+5)²
4.试说明两个连续奇数的平方差一定是8的倍数[用n表示]
(2n+1)²-(2n-1)²
=(2n+1+2n-1)(2n+1-2n+1)
=4n*2
=8n
所以是8的倍数
5.
(2ń+1)(2ń+1)(2ń+1).(2ń+1)
=(2-1)(2ń+1)(2ń+1)(2ń+1).(2ń+1)
=(2²-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=...
=2^64-1
(3X+2Y)²(3X-2Y)²
=[(3x+2y)(3x-2y)]²
=(9x-4y)²
=81x²-72xy+4y²
2.
(2X+6)²-2(3-X)²
=4(x+3)²-2(x+3)²
=2(x+3)²
=4x²+24x+36
3.填空:X²+10X+(25)=(x+5)²
4.试说明两个连续奇数的平方差一定是8的倍数[用n表示]
(2n+1)²-(2n-1)²
=(2n+1+2n-1)(2n+1-2n+1)
=4n*2
=8n
所以是8的倍数
5.
(2ń+1)(2ń+1)(2ń+1).(2ń+1)
=(2-1)(2ń+1)(2ń+1)(2ń+1).(2ń+1)
=(2²-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=...
=2^64-1
- -问几道数学题,1.简便计算:(3X+2Y)²(3X-2Y)²2:计算:(2X+6)²
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