An+1=3XAn+2n+1 怎么算出An+1-An=3(An-An-1)+2
An+1=3XAn+2n+1 怎么算出An+1-An=3(An-An-1)+2
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
数列{an}满足a1=1,且an=an-1+3n-2,求an
在数列an中,a1=2 an+1=an+3n则an=
数列an中,a1=3,an+1=an/2an+1,则an=?
an-an-1=2(n-1)
在等差数列{an}中,a1=1,a2=3,an+2=3an+1-2an(n属于N+)证明数列{an+1-an}是等比数列
已知数列{An}满足:A1=3 ,An+1=(3An-2)/An,n属于N*.1)证明:数列{(An--1)/(An--
已知数列{an}满足:a1=3,an+1=(3an-2)/an ,n∈N*.(Ⅰ)证明数列{(an-1)/an-2
设数列{an},a1=3,an+1=3an-2(n∈N*)
数列A1=1/3,An+1=An+An²/n²求证An>1/2+1/4n
数列{an}满足a1=1,an=3n+2an-1(n≥2)求an