sin(x+y)=1,则tan(2x+y)+tany=
sin(x+y)=1,则tan(2x+y)+tany=
sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(
已知sin(x+y)=1,求证:tan(2x+y)+tany=0
已知sin(x+y)=1,求证:tan(2x+3y)=tany
已知sin(x+y)=1,求证:tan(2x+y)+tany=0
若sin(x+y)=1/2,sin(x-y)=1/3,则tanx/tany等于?
证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))
tanX=2分之1,tan(x+y)=5分之2,那么tanY=?
已知2cos(2x+y)=cosy,求tan(x+y)tany的值
实数x,y满足tanx=x,tany=y,且|x|≠|y|,则sin(x+y)x+y−sin(x−y)x−y
已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)(详细步骤)