若多项式(2mx^2-x^2+5x+8)-(5x^2-3y+5x)的值与x的取值无关,求m^3-[2m^2-(5m-4)
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若多项式(2mx^2-x^2+5x+8)-(5x^2-3y+5x)的值与x的取值无关,求m^3-[2m^2-(5m-4)+m]的值.
![若多项式(2mx^2-x^2+5x+8)-(5x^2-3y+5x)的值与x的取值无关,求m^3-[2m^2-(5m-4)](/uploads/image/z/8433263-47-3.jpg?t=%E8%8B%A5%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%882mx%5E2-x%5E2%2B5x%2B8%29-%285x%5E2-3y%2B5x%29%E7%9A%84%E5%80%BC%E4%B8%8Ex%E7%9A%84%E5%8F%96%E5%80%BC%E6%97%A0%E5%85%B3%2C%E6%B1%82m%5E3-%5B2m%5E2-%EF%BC%885m-4%29)
(2mx^2-x^2+5x+8)-(5x^2-3y+5x)
=2mx^2-x^2+5x+8-5x^2+3y-5x
=2mx^2-6x^2+8+3y
=2(m-3)x^2+3y+8 的值与x的取值无关,所以 m-3=0,m=3
m^3-[2m^2-(5m-4)+m]
=m^3-(2m^2-5m+4+m)
=m^3-2m^2+5m-4-m
=m^3-2m^2+4m-4
=3^3-2x3^2+4x3-4
=17
=2mx^2-x^2+5x+8-5x^2+3y-5x
=2mx^2-6x^2+8+3y
=2(m-3)x^2+3y+8 的值与x的取值无关,所以 m-3=0,m=3
m^3-[2m^2-(5m-4)+m]
=m^3-(2m^2-5m+4+m)
=m^3-2m^2+5m-4-m
=m^3-2m^2+4m-4
=3^3-2x3^2+4x3-4
=17
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