复数(4-3i)^2(1+根号i)^10/(1+i)^12=?
复数(4-3i)^2(1+根号i)^10/(1+i)^12=?
复数(根号3 -i)/(1+根号3i)=
复数(1+根号3i)/(根号3-i)=?
复数z=(根号3+i)^4(2-2i)^4/(1-根号3i)^8的模|z|=
复数(-1+根号3i)^4/(1-i)^8等于
复数计算 (1-根号3i)^10-(1+根号3i)^10=?
复数1+3i/2+i=
复数 (3-i/1+i)^2=
复数除法 计算1+i/1-i,1/i,7+i/3+4i (-1+i)(2+i)/-i
复数5+3i/4-i=1+i
复数z=[(4-3i)^2]*[(-1+根号3*i)^10]/[(1-i)^12],求z的模.答案是400,
复数z=[(4-3i)^2]*[(-1+根号3*i)^10]/[(1-i)^12],求z的模