试用克拉默法则求下列线性方程组的解 x1+x3=1;2x1+2x2+3x3=3;x2+x3=-1
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试用克拉默法则求下列线性方程组的解 x1+x3=1;2x1+2x2+3x3=3;x2+x3=-1
x1+x3=1
2x1+2x2+3x3=3
x2+x3=-1
x1+x3=1
2x1+2x2+3x3=3
x2+x3=-1
![试用克拉默法则求下列线性方程组的解 x1+x3=1;2x1+2x2+3x3=3;x2+x3=-1](/uploads/image/z/2195488-64-8.jpg?t=%E8%AF%95%E7%94%A8%E5%85%8B%E6%8B%89%E9%BB%98%E6%B3%95%E5%88%99%E6%B1%82%E4%B8%8B%E5%88%97%E7%BA%BF%E6%80%A7%E6%96%B9%E7%A8%8B%E7%BB%84%E7%9A%84%E8%A7%A3+x1%2Bx3%3D1%3B2x1%2B2x2%2B3x3%3D3%3Bx2%2Bx3%3D-1)
根据克拉默法则,该线性方程组的系数行列式为
| 1 0 1 |
D = | 2 2 3 | = 1 x (2 - 3) + 1 x (2 - 0) = 1
| 0 1 1 |
而各个未知数对应的行列式分别为
| 1 0 1 |
D1 = | 3 2 3 | = 1 x (2 - 3) + 1 x (3 + 2) = 4
| -1 1 1 |
| 1 1 1 |
D2 = | 2 3 3 | = 1 x (3 + 3) - 1 x (2 - 0) + 1 x (-2 - 0) = 2
| 0 -1 1 |
| 1 0 1 |
D3 = | 2 2 3 | = 1 x (-2 - 3) + 1 x (2 - 0) = -3
| 0 1 -1 |
根据克拉默法则x1 = D1/D = 4,x2 = D2/D = 2,x3 = D3/D = -3.
| 1 0 1 |
D = | 2 2 3 | = 1 x (2 - 3) + 1 x (2 - 0) = 1
| 0 1 1 |
而各个未知数对应的行列式分别为
| 1 0 1 |
D1 = | 3 2 3 | = 1 x (2 - 3) + 1 x (3 + 2) = 4
| -1 1 1 |
| 1 1 1 |
D2 = | 2 3 3 | = 1 x (3 + 3) - 1 x (2 - 0) + 1 x (-2 - 0) = 2
| 0 -1 1 |
| 1 0 1 |
D3 = | 2 2 3 | = 1 x (-2 - 3) + 1 x (2 - 0) = -3
| 0 1 -1 |
根据克拉默法则x1 = D1/D = 4,x2 = D2/D = 2,x3 = D3/D = -3.
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